A Laboratory Assistant Received A Request Of 450 Ml Of A 60% Isopropyl Alcohol Solution But He Only Has 70% And 40% Isopropyl Alcohol Solutions On Han

A laboratory assistant received a request of 450 ML of a 60% isopropyl alcohol solution but he only has 70% and 40% Isopropyl alcohol solutions on hand. in order to produce the request how much of each I'll call solutions should he mix.

A. 150 ML of 70% and 300 ML of 40%
B. Do you hundred ML of 70% and 150 ML of 40%
C. 225 ML of each
D.200 ML of 70% and 250 ML of 40%

  Let x be the amount of 70%
y be the amount of 40%
request = 450mL of 60%
x + y = 450 -equation 1
x(0.70) + y(0.40) = 450(0.60) -equation 2
from equation 1
x = 450-y -equation1
substitute equation 1 to 2
(450-y)(0.70) + 0.40y = 450(0.60)
315-0.70y +0.40y = 270
-0.70y+0.40y =270-315
-0.30y = -45
y = -(-)45/0.30
y = 150mL
substitute to equation1
x = 450-y
x = 450-150
x = 300 mL
300mL 70%
150mL 40%

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